Write a function named pop1 that takes an argument named list, which is the head cell of a linked list, and removes the first normal cell (not the head cell), and returns the data contained in the cell. If there are no normal cells in the list (i.e. the list is empty), leave the list alone and return null instead. Code to construct an example linked list in the form used in the tests is given below.

var tail = { next: null };
var cell2 = { data: 12, next: tail };
var cell1 = { data: 45: next: cell2 };
var head = { next: cell1 };

javascript programming
exercise: functions 04

// ADD YOUR FUNCTION UNDER THIS LINE

var tail = { next: null };

var cellA2 = { data: 12, next: tail };
var cellA1 = { data: 45, next: cellA2 };
var cellA0 = { data: 99, next: cellA1 };
var headA = { next: cellA0 };

headB = { next: tail };

var cellC0 = { data: 111, next: tail };
var headC = { next: cellC0 };
  
var testAA = [
  [headA,99],
  [headB,null],
  [headC,111]
];

var argAAS = [];
for (var i=0;i<testAA.length;i++) {
  argAAS.push( [] );
  for (var j=0;j<testAA[i].length-1;j++) {
    argAAS[i].push( str(testAA[i][j]) );
  }
}

var testFunction = pop1;

function runTests(func,testAA) {
  var answerA = [];
  for (var i=0;i<testAA.length;++i)
    answerA.push( func.apply(null,testAA[i]) );
  return answerA;
}

function str(x) {
  return JSON.stringify(x);
}

run();
</script>

javascript programmingexercise: functions 04

javascript programming
exercise: functions 04