Write a function named variance that takes an argument named list, which is the head cell of a linked list in the form below and returns the variance of the numbers in the data properties. Hint: the best way to proceed is to keep a running sum of the numbers and also of the numbers squared, as well as keeping track of how many numbers are in the sum. Then compute the mean of the numbers squared as well as the mean of the numbers. Square the simple mean and subtract from the mean of the squares to get the answer.

var tail = { next: null };
var cell2 = { data: 12, next: tail };
var cell1 = { data: 45: next: cell2 };
var head = { next: cell1 };

javascript programming
exercise: functions 09

// ADD YOUR FUNCTION UNDER THIS LINE

var tailA = { next: null };
var cellA2 = { data: 2, next: tailA };
var cellA1 = { data: 5, next: cellA2 };
var headA = { next: cellA1 };

var tailC = { next: null };
var cellC3 = { data: 45, next: tailC };
var cellC2 = { data: 33, next: cellC3 };
var cellC1 = { data: 12, next: cellC2 };
var headC = { next: cellC1 };

var argAAS = [];
for (var i=0;i<testAA.length;i++) {
  argAAS.push( [] );
  for (var j=0;j<testAA[i].length-1;j++) {
    argAAS[i].push( str(testAA[i][j]) );
  }
}

var testFunction = variance;

function runTests(func,testAA) {
  var answerA = [];
  for (var i=0;i<testAA.length;++i)
    answerA.push( func.apply(null,testAA[i]) );
  return answerA;
}

function str(x) {
  return JSON.stringify(x);
}

run();
</script>

javascript programmingexercise: functions 09

javascript programming
exercise: functions 09